Maximum Acceleration and Coefficient of Friction

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Homework Help Overview

The discussion revolves around a physics problem involving maximum acceleration and the coefficient of friction for a utility truck and a cabinet on its bed. The original poster presents a scenario where half the weight of the truck is supported by its drive wheels, and questions are raised regarding the maximum acceleration achievable on dry concrete and whether a cabinet will slip during this acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the maximum acceleration based on the coefficient of friction and questions whether mass affects this acceleration. Some participants explore the implications of different weight distributions on acceleration and the relationship between maximum acceleration and surface friction.

Discussion Status

Participants are engaging with the original poster's calculations and reasoning, providing insights about the relationship between mass, friction, and acceleration. There is an exploration of how different vehicles might achieve maximum acceleration under similar conditions, with no explicit consensus reached on all points.

Contextual Notes

Participants note the potential neglect of other factors such as drag force and the performance characteristics of different systems, which may influence the practical application of the theoretical concepts discussed.

Jazz
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I'm teaching myself Physics (I really want to study Physics in college), and this is one of the few places where I can ask for help. I hope my questions aren't so silly.

1. Homework Statement


(a) If half of the weight of a small ##1.00×10^3kg## utility truck is supported by its two drive wheels, what is the magnitude of the maximum acceleration it can achieve on dry concrete? (b) Will a metal cabinet lying on the wooden bed of the truck slip if it accelerates at this rate?

Given/known data:

##m = 1.00×10^3\ kg##
##\mu_{s(rubber-dry\ concrete)} = 1.0##
##\mu_ {s(metal-wood)} = 0.5##

Homework Equations



##F_{net} = ma##
##f_{s(max)} = \mu_sN##

The Attempt at a Solution


[/B]
To solve (a), I understand than even when the wheels are rotating they are stationary relative to the ground. So as long as they are not slipping (by hitting the brakes hardly or by skiing on a wet surface) the following, I think, should hold:

##F_{net} = f_{s(max)}##
##F_{net} = \mu_{s(rubber-dry\ concrete)}N(0.5)##
##ma = \mu_{s(rubber-dry\ concrete)}mg(0.5)##
##a = \mu_{s(rubber-dry\ concrete)}g(0.5)##
##a = (1.0)(9.8\ m/s^2)(0.5)##
##a = 4.90\ m/s^2##In the case of (b), I think the slipperiness occurs because of Newton’s First Law. The cabinet will remain at rest while the truck will be moving at ##4.90\ m/s^2##. But this would be the same as the cabinet accelerating at ##4.90\ m/s^2## in the opposite direction while the truck remains at rest; but only if:

##m_{cabinet}a > \mu_ {s(metal-wood)}m_{cabinet}g##
##a >\mu_ {s(metal-wood)}g##
##4.90\ m/s^2 > (0.5)(9.8\ m/s^2)##
##4.90\ m/s^2 > 4.90\ m/s^2##

Since the inequality doesn't hold, the cabinet will not slide.

Doubts:

As you can see, in (a) and (b) mass cancels. Does it mean that the maximum acceleration only depends on the ##\mu_s## of the surfaces (and on the planet I’m driving)?

if my bicycle’s wheels and the wheels of a racing car have the same ##\mu_s## (on the same road with the same conditions), does it mean that maximum acceleration of both is the same? The difference is in how quickly the car and I can reach that acceleration, right?

Probably I'm neglecting other things that come into play (like drag force), but is this assumption theoretically correct?

Thanks!
 
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Jazz said:
As you can see, in (a) and (b) mass cancels. Does it mean that the maximum acceleration only depends on the ##\mu_s## of the surfaces (and on the planet I’m driving)?
Yes, and this can be predicted by dimensional analysis.
if my bicycle’s wheels and the wheels of a racing car have the same ##\mu_s## (on the same road with the same conditions), does it mean that maximum acceleration of both is the same?
Yes, except that the weight may be distributed differently between front and back. As your calculation has shown, the greater the share of load on the driving wheels the better the acceleration (but the worse the steering).
The difference is in how quickly the car and I can reach that acceleration, right?
There need be no delay n reaching maximum acceleration. It may not feel like it, but when you put your full weight on the forward pedal, in horizontal crank position, in bottom gear, you are at maximum acceleration immediately.
 
haruspex said:
Yes, and this can be predicted by dimensional analysis.

Thanks for answering.

Yes, except that the weight may be distributed differently between front and back. As your calculation has shown, the greater the share of load on the driving wheels the better the acceleration (but the worse the steering).

So, as an example, this can be considered one of the reason why some tractors have a sort of movable axle to use when transporting heavy load.

There need be no delay n reaching maximum acceleration. It may not feel like it, but when you put your full weight on the forward pedal, in horizontal crank position, in bottom gear, you are at maximum acceleration immediately.

Then, the difference between the two is in how much times that acceleration can be mantained, right?
 
Jazz said:
Then, the difference between the two is in how much times that acceleration can be mantained, right?
It is likely that human legs and a car engine have different performance characteristics, but I'm no expert on such matters.
 

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