Solving Mechanics Equation:Car X, Car Y, v, a, b

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Car X travels at a constant speed v towards stationary Car Y, which starts moving with uniform acceleration a when Car X is b meters behind. The problem requires showing that Car X does not overtake Car Y, leading to the conclusion that v must be less than the square root of 2ab. Using the equation v² = u² + 2as for Car Y, it is determined that the final speed of Car Y is v = √(2ab). Since Car Y accelerates and reaches this speed, it must be true that √(2ab) > v, confirming that Car X does not overtake Car Y. The analysis indicates that the relationship between the speeds and acceleration is crucial for solving the mechanics equation.
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Homework Statement



Car X moves with a constant speed of v m/s on a straight road heading towards a stationary car Y on the road. When car X is b m behind car Y, car Y starts to move with a uniform acceleration of a m/s^2 in the same direction as the direction of car X until it achieves a constant speed of v m/s . If car X did not overtake car Y, show that v<root(2ab)

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The Attempt at a Solution



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Hint; use the equation v2 = u2 + 2 * a * s

where u = initial velocity and s = displacement
 
ok ,

so for car Y , usign

v^2=u^2+2as

v^2=2ab

v=root(2ab) and this is the final speed of car y

And car X did not overtake car Y , so Vy>Vx

root(2ab)>v

Is it that simple? This question has 5 marks . Thanks anyways .
 
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