Solving Mechanics Equation:Car X, Car Y, v, a, b

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SUMMARY

The discussion focuses on solving a mechanics equation involving two cars, X and Y, where car X travels at a constant speed of v m/s and car Y accelerates from rest at a rate of a m/s² until it reaches the same speed. The key conclusion is that if car X does not overtake car Y, the relationship v < sqrt(2ab) must hold true. The equation v² = u² + 2as is utilized to derive that the final speed of car Y is v = sqrt(2ab), confirming that car Y's speed must exceed that of car X for the overtaking condition to be satisfied.

PREREQUISITES
  • Understanding of kinematics, specifically uniform acceleration.
  • Familiarity with the equation of motion: v² = u² + 2as.
  • Knowledge of basic algebra and square root operations.
  • Concept of relative motion between two objects.
NEXT STEPS
  • Study the principles of kinematics in depth, focusing on uniform acceleration.
  • Learn about relative motion and how it applies to multiple objects in motion.
  • Explore advanced applications of the equation of motion in real-world scenarios.
  • Practice solving similar mechanics problems to reinforce understanding.
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Homework Statement



Car X moves with a constant speed of v m/s on a straight road heading towards a stationary car Y on the road. When car X is b m behind car Y, car Y starts to move with a uniform acceleration of a m/s^2 in the same direction as the direction of car X until it achieves a constant speed of v m/s . If car X did not overtake car Y, show that v<root(2ab)

Homework Equations





The Attempt at a Solution



I need to get started.
 
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Hint; use the equation v2 = u2 + 2 * a * s

where u = initial velocity and s = displacement
 
ok ,

so for car Y , usign

v^2=u^2+2as

v^2=2ab

v=root(2ab) and this is the final speed of car y

And car X did not overtake car Y , so Vy>Vx

root(2ab)>v

Is it that simple? This question has 5 marks . Thanks anyways .
 

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