Solving Military HW: Position & Speed at Time 0s

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Homework Help Overview

The discussion revolves around a problem related to simple harmonic motion (SHM), specifically involving a military hardware system characterized by an amplitude of 23 cm and a frequency of 55 Hz. The problem seeks to determine the time at which the system passes through a position of 15 cm and the position when the speed is 200 m/s, starting from the origin at time 0s.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate angular frequency and maximum velocity but questions the use of trigonometry and the unit circle in solving the problem. They express uncertainty about whether to approach SHM in terms of circular motion or linear movement.

Discussion Status

Some participants provide equations related to SHM and suggest using trigonometric functions to find the time when the position is 15 cm. However, there is a lack of clarity for the original poster regarding the variables and how to manipulate the equations to find the desired time.

Contextual Notes

Participants are grappling with the definitions and relationships between position, velocity, and time in the context of SHM, indicating potential confusion about the underlying concepts and the specific parameters involved in the problem.

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Homework Statement



A system is testing some military HW which has an amplitude of 23cm and frequency of 55Hz. At time 0s it is at the origin.

Homework Equations



At what time does it pass through 15cm?
When the speed is 200ms^-1 what is the position?

The Attempt at a Solution



omega = (2pi) * 55 = 346 r^s-1
max V = 23 * 346 = 7958 -- is that right??

To find the time, do I need to use trigonometry and the unit circle? No clues about the second one. Can SHM problems be found with the unit circle? Do I need to only use the SHM equations?

Should I think SHM in terms of the unit circle or movement going only up and down and not in a circle at all?

I'm really stuck, thanks for any help.
 
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You have that x=Xsin(ωt+φ) and you found that ω=346 rad/s and φ=0, X=23.

Hence you have x = 23sin(346t).

So when x=15, you just need to use standard trigs.

siny=a ⇒ y=sin-1(a)


For the second one, velocity 'v' is related to 'x' by v = dx/dt.
 
Sorry, I don't get it.

What is a? I looked at that first equation but how do I find t from that?

Thanks,

Jim.
 
jimmy42 said:
Sorry, I don't get it.

What is a? I looked at that first equation but how do I find t from that?

Thanks,

Jim.

x = 23sin(346t).

then you have 15=23sin(346t). Make sin(346t) the subject and then take the inverse sine of that.
 

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