Solving Momentum Problem: Superman & Metropolis Express Collision

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Homework Help Overview

The problem involves a collision scenario between Superman and a train, focusing on momentum and forces. The context includes calculating Superman's velocity before the collision, the average force exerted by Superman on the train, and the average force exerted by the train on Superman.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply conservation of momentum to find Superman's velocity, but expresses confusion over the resulting value. Some participants question the validity of the calculations and the implications of the momentum involved. Others raise concerns about the average force calculations and their physical significance.

Discussion Status

Participants are actively engaging with the calculations, identifying potential errors and questioning the assumptions made. There is a recognition of the large momentum of the train, and discussions are ongoing regarding the average forces involved in the scenario.

Contextual Notes

There is mention of specific time constraints for the forces being calculated, and participants are grappling with the implications of their results in relation to the masses involved.

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Homework Statement



Lois Lane has been tied to the tracks and the Metropolis Express (m=200, 000 kg) is racing toward her at a velocity of +30 m/s. Superman (m=100kg) arrives just in time and comes hurtling at the train, collides with it, and stops it just before it runs over Lois. NOTE: Both Superman and the train come to a stop.

a)What was Man of Steel's velocity prior to his collision with the train?

b) It took 0.20 seconds for the train, and Superman, to come to a stop, what was the average force exerted by Superman on the train?

c) What was the average force exerted by the train on Superman?

Homework Equations





The Attempt at a Solution



i thought for part a:

200000(0)+100(v)=200000(30)+100(0)

v=6000 m/s?! it doesn't make sense..

part b)

J=Fave(t)
P=m(V)

100(v)=Fave(.2)

I realized i had to find Superman's velocity...
 
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Check your calculation, your answer is smaller than what it should be (by a factor of ten.)

But even with your smaller answer, why doesn't it make sense? A 200,000 kg train moving at 30 m/s has a lot of momentum.
 
cdotter said:
Check your calculation, your answer is smaller than what it should be (by a factor of ten.)

But even with your smaller answer, why doesn't it make sense? A 200,000 kg train moving at 30 m/s has a lot of momentum.

sorry, it was 60,000!
what does it mean for the average force exerted by the train on superman?!
 
also, i got 60, 000, 000 N for part b...
which doesn't seem right for superman who has a mass of 100 kg..
Favg(.2)=100(60,000)
 

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