Solving Momentum Transfer: 2 kg Steel Balls Colliding

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A 2 kg steel ball A traveling west at 5 m s–1 collides elastically head-on with a
stationary ball B also of mass 2 kg. Without doing any calculations, state the
velocities (including directions) of the two balls after collision.

Initial momentum = final momentum = 10

I got 10/4 since I assumed it was coupled but it says that V of a is 0 and V of b is 5.
Even so, there would be two variables; how would I solve this? Could anyone please calrify for me?

When I did it separately I got 5 = mv(a) + mv(b)
 
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Procrastinate said:
A 2 kg steel ball A traveling west at 5 m s–1 collides elastically head-on with a
stationary ball B also of mass 2 kg. Without doing any calculations, state the
velocities (including directions) of the two balls after collision.

Initial momentum = final momentum = 10

I got 10/4 since I assumed it was coupled but it says that V of a is 0 and V of b is 5.
Even so, there would be two variables; how would I solve this? Could anyone please calrify for me?

When I did it separately I got 5 = mv(a) + mv(b)

You can easily state the direction, but they didn't give too much info about a and b, and well they said elastically so kinetic energy is conserved. You'll get another equation there.