Solving Newton's Laws: Get Help Here!

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SUMMARY

This discussion focuses on solving problems related to Newton's Laws of Motion, specifically addressing tension in a system and calculating net force. User asi123 confirmed that their calculated tension (T2 = 8.736) is correct. The net force is defined as the vector sum of all forces acting on an object, which, according to Newton's second law, equals mass times acceleration. The conversation also emphasizes the importance of considering only horizontal components when calculating net force in specific scenarios.

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  • Familiarity with vector addition of forces
  • Knowledge of centripetal acceleration
  • Basic algebra for solving equations
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  • Learn about vector components and their role in force calculations
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators seeking to clarify concepts related to Newton's Laws of Motion.

asi123
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Homework Statement



In the attach

Homework Equations



Newton Laws

The Attempt at a Solution



Ok, I did the first one, came up with T2 = 8.736, is that right?
What is the net force?
How do I do the third one?

10x in advance.
 

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asi123 said:
Ok, I did the first one, came up with T2 = 8.736, is that right?
What is the net force?
How do I do the third one?

Shalom asi123! :smile:

Yes, your T2 is right! :smile:

The net force is the vector sum of all the forces.

(By Newton's second law, it will be equal to mass times acceleration.)

Just add all the forces (obviously, the vertical components cancel, so you only have to add the horizontal components :wink:)

The use the formula for centripetal acceleration to find the speed. :smile:
 
tiny-tim said:
Shalom asi123! :smile:

Yes, your T2 is right! :smile:

The net force is the vector sum of all the forces.

(By Newton's second law, it will be equal to mass times acceleration.)

Just add all the forces (obviously, the vertical components cancel, so you only have to add the horizontal components :wink:)

The use the formula for centripetal acceleration to find the speed. :smile:

Shalom Shalom.
10x.
 

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