Solving ODE with Integrating Factor Method: (1-x/y)dx + (2xy+x/y+x^2/y^2)dy = 0

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The forum discussion focuses on solving the ordinary differential equation (ODE) given by (1 - x/y)dx + (2xy + x/y + x^2/y^2)dy = 0. The user initially struggled with applying the integrating factor method and considered substitutions due to the complexity of the terms. Ultimately, the solution was achieved using the substitution u(y) = x/y, leading to the final result: C = ln|x| + ln|y| - x/y + y^2. Two strategies were successfully employed: one with the integrating factor and another with substitution.

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manenbu
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Homework Statement



Solve:
(1-\frac{x}{y})dx + (2xy + \frac{x}{y} + \frac{x^2}{y^2})dy = 0

The Attempt at a Solution



No idea what strategy to use here. Tried using an integrating factor, but no success. A lot of x/y in here makes me think I need to use a substitution, but there's also "xy" in here which doesn't help me. What should I do?
 
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How did you try using the integrating factor? Did you try multiplying by "x^m*y^n" and then solving the integers "m" and "n"?
 


I tried using the formulas:

<br /> F(x) = \frac{\frac{\partial M}{\partial y} - \frac{\partial N}{\partial x}}{N}<br />
And then:
\mu(x) = e^{\int F(x) dx}

(there's also a similar one for y, with signs reversed and M instead of N in the denominator).

Had trouble in the F(x) part - couldn't get a function of x only (or y, for that matter).
 
Last edited:


Ok! Solved it. Missed a little thing on my side.

Thanks anyway! :)
 


The substitution u(y)=\frac{x}{y} works out nicely.
 


C = \ln{|x|} + \ln{|y|} - \frac{x}{y} + y^2

That's the solution, in 2 different strategies.
One using the integrating factor, second using your substitution. Thanks for pointing it out. :)
 

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