Solving Phase Change Question: What is the specific heat?

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The discussion revolves around a homework problem involving phase changes and specific heat calculations. An unknown solid at 235°C is added to ice at -20°C, and both reach thermal equilibrium at 120°C. Participants express confusion about incorporating phase changes and the concept of surroundings in their calculations. The key to solving the problem lies in recognizing that heat gained equals heat lost, requiring the calculation of heat for various phases of water and the latent heat involved. The conversation emphasizes the need for clear equations and understanding the heat transfer process in calorimetry.
dnartS
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We have a tricky question for homework that is starting our new unit of phase changes, after we have been doing calorimetry

120.0g of an unknown solid at 235*c is added to a 1.5kg piece of ice at -20*c inside a styrofoam container. After a period of time, both substances areat 120*c. What is the specific heat of the unknown material in kJ/g.*c and kcal/g.*c?

Here's what I was thinking yesterday:

Qsurround = Mh20Ch20ΔT ([120]-[20])
...

but I'm confused and that wouldn't account for the phase change in the question.

My teacher gave us this hint today:

"Qsurroundings = Q1 + Q2 + Q3 + Q4 + Q5"


Any help would be great thanks :)
 
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Not sure what surroundings have to do here. It is as usual - heat gained equals heat lost. If you started with ice and ended at 120 deg C, you had two phase changes on the way. Thus heating of the water can be expressed as sum of five parts - three being heating of water in different states of aggregation, two being latent heat of the phase change.

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Borek said:
Not sure what surroundings have to do here. It is as usual - heat gained equals heat lost. If you started with ice and ended at 120 deg C, you had two phase changes on the way. Thus heating of the water can be expressed as sum of five parts - three being heating of water in different states of aggregation, two being latent heat of the phase change.

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Yes, so if Ch20(s) = 2.05 J/g.*c and Ch20(g) = 2.08 J/g.*c and we need to find Qsurroundings of each of the 5 parts, what would I do?
 
Sorry, I have no idea what you mean by surroundings. In the calorimeter we did everything possible to isolate everything involved from the surroundings, so we have to deal with heat gained by things that were cold, and heat lost by things that were initially hot.

I can only guess that by surroudnings you mean things OTHER then the substance for which you make calculations, but it doesn't make much sense in this case.

Let's start with water - there are three stages of heating, an you have already listed equation that have to be used (although you listed it in a very cryptic way - please use * for multiplication, guessing where are the borders between variable names in Mh20Ch20ΔT is a waste of time). Can you calculate amount of heat required for raising temperature of ice to the melting point?

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dnartS said:
Can you calculate amount of heat required for raising temperature of ice to the melting point?
How would I calculate the amount of heat required for raising temperature of ice to 0*c?

How would you calculate the amount of heat required for raising temperature of ANY substance by ΔT?

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