Solving Physics Motion: When Does Green VAN Overtake Red CAR?

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Homework Help Overview

The discussion revolves around a physics problem related to motion, specifically determining the instant when a green van overtakes a red car. Participants are exploring the relationships between displacement and velocity, as well as the graphical representation of these concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to set up equations for displacement and velocity, considering the need for equal displacements. Some participants discuss the use of linear functions and the area under the graph to find displacement.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on writing equations based on given points. There is a mix of confusion and attempts to clarify the approach, with one participant expressing a breakthrough in understanding.

Contextual Notes

There is mention of constraints regarding the use of linear functions, as the problem is presented graphically, which may affect the methods discussed for finding displacement.

Hollysmoke
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I'm having trouble with the 2nd part of this question, which asks at what instant the VAN (Green) overtakes the CAR (Red). I drew out the diagram. From what I believe, the displacements have to be equal so would I have to substitute two equations in each other?

http://img371.imageshack.us/img371/4530/diag2nj.png
 
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That's correct

marlon
 
I'm just lost on how to start the question...my friend and I are discussing it but bleh >_<
 
Well write down the equation of v as a function of time t.

You know that :
(30,15) and (0,0)
(60,20) and (0,0)

are the couples of points that belong to each linear curve.

Can you write down the equation of a linear function when these points have been given ?

marlon
 
well we're not supposed to use linear function...it's on agraph so it displacement would the area underneath the graph...still stuck on it.
 
Hollysmoke said:
well we're not supposed to use linear function...it's on agraph so it displacement would the area underneath the graph...still stuck on it.
i don't think you are getting the point.

Just set up v = a*t

by using [tex]y-y1 = \frac{y2-y1}{x2-x2}(x-x1)[/tex]

The (x1,y1) and (x2,y2) have been given. Keep in mind that x is t and y is v here

Or you can indeed get the a by calculating the surface under the curve.

Anyhow, the result must stay the same.

marlon
 
Omg I Figured It Out. Thank You Marlon!
 

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