Solving Physics Problems: 25N Force, 2.5 kg Block, and 35deg Incline

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SUMMARY

The discussion focuses on solving a physics problem involving a 25 N force acting on a 2.5 kg block on a 35-degree incline. The key calculations include determining the work done by the applied force, friction, and gravitational force. The correct formula for work is applied, leading to a calculated work of 102.4 J for the 25 N force. Participants emphasize the importance of considering the normal force and gravitational force in the calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of work-energy principles
  • Familiarity with trigonometric functions in physics
  • Basic understanding of friction and normal force concepts
NEXT STEPS
  • Calculate work done by friction using the coefficient of friction and normal force
  • Analyze gravitational force components on an incline
  • Explore net force diagrams for inclined planes
  • Review the work-energy theorem in physics
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Students studying physics, educators teaching mechanics, and anyone interested in solving problems related to forces on inclined planes.

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anyone physics experts know how to do this questions?

A force of 25 N parallel to a 35degrees inclined plane pulls a 2.5 kg block 5 m up the plane at
constant speed.
(a) How much work has been done by the 25 N force?
(b) much work has been done by friction?
(c) How much work has been done by the gravitational force?
 
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What have you done to try and solve the question? Where specifically are you have problems?
 
work=F(average)*(cos theta)*distance
friction=coefficient of friction * Normal force
gravity is always 9.80m/s^2 on earth
 
this is what i got so far. W = F * distance

so by the diagram I got:

W = 25 N * 5m * cos 35

but i know that's wrong... i dont' know how i incorporate the mass
 
multiply the mass by gravity, but remember that gravity will be straight down and the normal force is perpendicular to the block, so use a net force diagram to sort out the remaining forces ... hope that helps, makes more sense in my head than it does typed, lol
 
WCU said:
multiply the mass by gravity, but remember that gravity will be straight down and the normal force is perpendicular to the block, so use a net force diagram to sort out the remaining forces ... hope that helps, makes more sense in my head than it does typed, lol


what part of the question are you referring to?
 
for part a i got 102.4 J. does that look right?
 

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