Solving Power Series Problems: Finding 2 Solutions

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SUMMARY

This discussion focuses on solving second-order linear differential equations using power series methods. The key point is that to find two independent power series solutions, specific initial conditions must be applied, such as setting coefficients c0=1 and c1=0 for one solution and c0=0 and c1=1 for the other. This approach ensures the generation of two distinct solutions that can be expressed as linear combinations of the independent solutions. Understanding the role of these initial conditions is crucial for correctly applying power series techniques in differential equations.

PREREQUISITES
  • Understanding of second-order linear differential equations
  • Familiarity with power series expansions
  • Knowledge of initial value problems
  • Basic calculus, including differentiation and series manipulation
NEXT STEPS
  • Study the method of Frobenius for solving differential equations
  • Learn about the Wronskian and its role in determining linear independence of solutions
  • Explore specific examples of power series solutions for different differential equations
  • Investigate the implications of even and odd functions in power series solutions
USEFUL FOR

Mathematics students, educators, and anyone involved in solving differential equations, particularly those interested in power series methods and initial value problems.

joker2014
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Hello.

I've been solving power series problems where the question asks to find 2 power series solutions.

I can solve it almost all, I can find the recurrence solution... however while checking the solutions, I see some answer solutions they used c0=1 and c1=0 to find the 2 solutions, and some answer solutions they did not use that.

am I missing something? I don't even understand why they used c0=1 c1=0, and when should i use or not.
 
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Could it have something to do with the function being even or odd?
 
It's not very clear what question you are asking! I think you are talking about a second order linear differential equation and you should understand that such equations will have two independent solutions such that all solutions can be written as a linear combination of those two.

In particular, given second order linear differential equation p(x)y''+ q(x)y'+ r(x)y= 0. In order to get a specific solution you would have to be give two additional conditions and the simplest would be the two initial value conditions, y(0)= 0, y'(0)= 1 and y(0)= 1, y'(0)= 0.

Of course, if we write the solutions in terms of a power series, y(x)= a_0+ a_1x+ a_2x^2+ \cdot\cdot\cdot then y'(x)= a_1+ 2a_2x+ 3a_3x^2+ \cdot\cdot\cdot so that y(0)= a_0 and y'(0)= a_1. So the simplest way to find two independent solutions, as power series, is to require that, in one, a_0= 1 and a_1= 0 while in the other a_0= 0 and a_1= 1.
 
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