Solving Projectile Motion of an Object

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Homework Help Overview

The discussion revolves around calculating the projectile motion of an object, specifically focusing on a long jumper's take-off velocity and its components. The problem involves determining the horizontal and vertical components of the initial velocity given a specific angle and speed.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using vector components to solve for the horizontal and vertical speeds. There is mention of drawing a right-angled triangle to visualize the components. Some participants suggest considering the absence of external forces in the horizontal direction.

Discussion Status

The discussion includes attempts to clarify the calculations for the horizontal and vertical components of velocity. Some guidance has been offered regarding the use of trigonometric functions, and there is an acknowledgment of the need to follow specific steps before applying analytical methods.

Contextual Notes

Participants are navigating the constraints of the problem, including the angle of take-off and the assumption of neglecting air resistance in the analysis of horizontal velocity.

Paulo2014
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[SOLVED] Projectile motion

Homework Statement


How do you calculate the projectile motion of an object in the following question?

John is a long jumper. He runs down a track, and jumps as far as he can horizonally. Her take-off velocity is 6.4 m s-1 at 20 degrees from the horizontal.

a) show that the horizontal component of her initial velocity is 6.0m s-1

b) Show that the vertical component of her initial velocity is 2.2 m s-1


c) Explain why the horizontal component of her velocity is constant.



The Attempt at a Solution



I know that for a) you use vectors to solve it but I don't know what to do after that and for the others I have no idea what to do so any help is appreciated
 
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… right-angled triangle …

Hi Paulo! :smile:

For a) and b), draw a right-angled triangle.

Can you now see what combination of horizontal and vertical speeds makes 6.4 m s-1 at 20 degrees from the horizontal? :smile:
 
Initial velocity: 6.4 m/s

a)Horizontal component= 6.4 * cosine20 degrees.
>>6 m/s.
b)Vertical component= 6.4 * sine 20 degrees.
>>2.2 m/s.
c)Since the velocity is constant due to the fact that there are no external forces acting in the horizontal direction, if you neglect air resistance, therefore, the horizontal velocity of a projectile is constant.

Remember these are just for your reference.You must first follow the steps as mentioned by "tiny tim" and then look up the analytical method i have solved for you.
 
Thanks guys for being so helpful
 

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