Solving Quadratic Equations with Binary Operator $\otimes$

[karush]

Define the binary operater $\otimes$ by
$a\otimes b = a^2+b+9$
Find
a. $6\otimes 4 = 6^2+4+9 = 36+13 = 49$
b. $3\otimes 3 = 3^2+3+9 = 9+13 = 22$
c $4\otimes 6 = 4^2+6+9 = 16+15 =21$
d. $i\otimes p = i^2+p+9$

i think its ok but most math errors are in simple arithmetic

 

[Evgeny.Makarov]

b and c have arithmetic errors.

The best way to check the answers is to write a function in some programming language and run it on your inputs. For example, in Python the function would be

def f(x, y):
  return x**2 + y + 9

Then you can run f(6, 4) and so on in an interpreter.

 

[karush]

Define the binary operater $\otimes$ by
$a\otimes b = a^2+b+9$
Find
a. $6\otimes 4 = 6^2+4+9 = 36+13 = 49$
b. $3\otimes 3 = 3^2+3+9 = 9+13 = 22$
c $4\otimes 6 = 4^2+6+9 = 16+15 =21$
d. $i\otimes p = i^2+p+9$

i think its ok but most math errors are in simple arithmetic

b and c have arithmetic errors.

The best way to check the answers is to write a function in some programming language and run it on your inputs. For example, in Python the function would be

def f(x, y):
  return x**2 + y + 9

Then you can run f(6, 4) and so on in an interpreter.

b and c have arithmetic errors.

The best way to check the answers is to write a function in some programming language and run it on your inputs. For example, in Python the function would be

def f(x, y):
  return x**2 + y + 9

Then you can run f(6, 4) and so on in an interpreter.

ummm is that under colcalc
at least I saw it there when one class was teaching us the programs

 

[Evgeny.Makarov]

Python is a programming language that can be used in different environments: CoCalc, Jupyter Notebook, PyCharm by JetBrains or simply from the command line. Use whatever tool you are familiar with, or use any other programming language.

It's a good idea to quote only relevant passages.

 

[karush]

Find (corrected)
a. $6\otimes 4 = 6^2+4+9 = 36+13 = 49$
b. $3\otimes 3 = 3^2+3+9 = 9+13 = 21$
c $4\otimes 6 = 4^2+6+9 = 16+15 =31$
d. $i\otimes p = i^2+p+9$

 

[Evgeny.Makarov]

$3^2+3+9=9+12$.

 

[karush]

gotcha

3\otimes 3 = 3^2+3+9 = 9+12= 21