Solving Redox Equations: Cathodic Reaction of Oxygen

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SUMMARY

The discussion centers on the cathodic reaction of oxygen in redox equations, specifically evaluating two half-equations. The first equation, O2 + 2H2O + 4e- → 4OH-, is noted as the most common in lecture notes. The second equation, O2 + 4H+ + 4e- → 2H2O, is also valid but occurs under different conditions. Both equations are legitimate, and the choice between them depends on the specific electrochemical context.

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  • Understanding of redox reactions and half-equations
  • Familiarity with electrochemical potentials
  • Knowledge of oxidation states and electron transfer
  • Basic concepts of aqueous chemistry
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Chemistry students, electrochemists, and anyone studying redox reactions in aqueous solutions will benefit from this discussion.

big man
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Homework Statement


Write the half equation for the cathodic reaction of oxygen

The Attempt at a Solution


Now I know that the cathodic reaction will be reduction and so the oxygen will be gaining electrons. I thought I had the answer from the lecture notes, but then I thought of another possible equation that would work too and I don't know which one is right??

The two equations are as follows:
equation from notes( the notes say that this is the most common)
[tex]O_2 + 2H_2O + 4e^- ->4OH^-[/tex]

the equation I came up with
[tex]O_2 + 4H^+ + 4e^- ->2H_2O[/tex]

Are these just two possible half equations for the cathodic reaction of oxygen or is one wrong??

Thanks for your time
 
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I think we need more context here. Both reactions are legal, and likely occur at quite different potentials, so additional details are necessary.
 

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