Solving Redox Equations Involving Cl2 in Basic Solution

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SUMMARY

The discussion focuses on balancing the redox equation Cl2 -> Cl- + ClO3- in a basic solution. Participants emphasize the importance of correctly handling half-reactions, particularly the involvement of Cl2 in both the oxidation and reduction processes. The solution involves recognizing that 6Cl2 is necessary for proper electron cancellation, leading to a balanced equation. Tools such as equation balancers and stoichiometry calculators are recommended for assistance in these calculations.

PREREQUISITES
  • Understanding of redox reactions and half-reaction methods
  • Familiarity with balancing chemical equations in basic solutions
  • Knowledge of oxidation states and electron transfer
  • Experience with using equation balancers and stoichiometry calculators
NEXT STEPS
  • Research the method for balancing redox reactions in basic solutions
  • Learn how to use equation balancers effectively for complex reactions
  • Explore the concept of oxidation states in detail
  • Study the principles of stoichiometry in chemical reactions
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Chemistry students, educators, and anyone involved in balancing redox equations or studying electrochemistry will benefit from this discussion.

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Homework Statement


Cl2 -> Cl- + ClO3-
(in basic solution)

Homework Equations


The Attempt at a Solution


Well, I've tried messing around with the half reactions but since Cl2 is involved in both, they don't seem to do much good.

e + Cl2 -> Cl-
Cl2 -> ClO3- + 5e

Normally, I would multiply the top by 5e to let the electrons cancel, but then there's a Cl2 and a 5Cl2 so that doesn't appear to work...

Anyone have any ideas on how to do this?
 
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