Solving Resultant Force: F1+F2+F3 in Standard Polar Form

[keith421]

Missed a day of school due to a car accident in the blizzard and he went over resultant forces. Have this problem to due and I'm not quite sure on what I would do to solve this.

http://img502.imageshack.us/img502/2087/blawu.jpg

add the three forces f1 f2 and f3 both analtically and graphically to find the resultant force r = f1 + f2 + f3 give the net force r in standard polar form.

edit ; that is 45deg. by the way

 

[rl.bhat]

Hi keith421, welcome to PF.
Resolve f2 into vertical and horizontal components.T
Then find ΣFx and ΣFy. Then find the resultant.

 

[jhae2.718]

Try breaking f2 into its x and y components and then take ΣF_x and ΣF_y.

Then put your answer into polar form by finding the magnitude of the resultant force and its direction.

Edit: Too late...

 

[keith421]

ok so i got the x and y component for F2, both 56.56.
i then subtracted F1 10n from F2x 56.56 which i got 46.56
then subtracted F3 30n from F2y 56.56 which got me 26.56

then square root of 46.56²+26.56² = squartroot of c. which got me 53.6n.

then did sin(26.56/53.6)= .4995. then sin-1(4.995)= 29.70.

so 53.6 N and 29.70 NE. is this correct?

what do i do for graphing?

 

[keith421]

http://img96.imageshack.us/img96/2347/76576450.png
is this the correct way of graphing this?

 

[rl.bhat]

Yes.

 

[keith421]

Thanks for the help, goodnight!