Replace all the loads on the beam with one resultant force.

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SUMMARY

The discussion focuses on calculating the resultant force acting on a beam with multiple loads, specifically F1=100kN, F2=50kN, and F3=60kN, positioned at specified distances. The resultant force R is determined to be 90kN directed downwards. The moment about the left end is calculated to be 65 kN·m in the counterclockwise direction. The resultant force is applied at a distance of 0.722m from the left end of the beam.

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Homework Statement



Knowing the distance d=1.5m, determine the resultant of the loads acting on the beam shown in the attachment. Specify the point of application of this resultant on the beam.

Given data: F1=100KN, l1=1m. F2=50kN,l2=1.5m. F3=60KN, l3=4m.
Variables: Resultant Force R, and its lever arm L.

Homework Equations



R=F1+F2-F3=90KN(Pointing downwards)
Take the most left point as reference:
M=-F1*l1-F2*l2+F3*l3=65 KN*m (Counterclockwise direction)

The Attempt at a Solution


The problem I have is that, since R is pointing downwards, it will never create a counterclockwise direction moment, hence this problem cannot be solved. But on my book, anwser is given like this:
R=90KN downwards @0.722m from the left end

Thank you for helping me:)
 

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You have the 50 kN load located at 4m from the left end. This location does not match the attached diagram.
 
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SteamKing said:
You have the 50 kN load located at 4m from the left end. This location does not match the attached diagram.

Sorry for my mistake, corrected just now
 

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