Solving Rolling Question Homework: Speed & Acceleration

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A tire with a radius of 0.5 m rotates at 200 revolutions per minute, leading to a speed of approximately 10π/3 m/s for a stone on its surface. The discussion clarifies that with constant angular velocity, the angular acceleration is zero, resulting in zero tangential acceleration. The focus is on calculating radial acceleration, which is determined using the formula a_r = v^2/r. The participants express frustration over the quality of exam questions. Overall, the key takeaway is the distinction between tangential and radial acceleration in this context.
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Homework Statement


Hi again ,, my second one is easy:

A tire 0.5 m in radius rotates at a constant rate of 200 rev/min. Find the speed and
acceleration of a small stone stuck on the surface of the tire (on its outer edge).


Homework Equations





The Attempt at a Solution


the Speed of the rock is easy to get (W=200 rev/min = (20*pi)/3 rad/s = (10*pi)/3 m/s)
about the acceleration : should I get the tangent acceleration or the radial ??
 
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Constant angular velocity means that the angular acceleration is zero. So the tangential acceleration is zero.
 
so the question means i should get the tangent acceleration right not the radial one ?
 
Lord Dark said:
so the question means i should get the tangent acceleration right not the radial one ?

a_t = \alpha r

a_r = \frac{v^2}{r}


seeing as that \alpha=0, which one do you think you should find?
 
rock.freak667 said:
a_t = \alpha r

a_r = \frac{v^2}{r}


seeing as that \alpha=0, which one do you think you should find?

lol ,, got it :) ,, thanks ,, exam questions are so poor -_-
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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