Solving Separable Differential Equation: dy/dx = (6x^2)/((1+x^3)y)

  • Thread starter Thread starter myusernameis
  • Start date Start date
  • Tags Tags
    Diff eq
Click For Summary
SUMMARY

The discussion centers on solving the separable differential equation dy/dx = (6x^2)/((1+x^3)y). Participants confirm that after integration, the equation simplifies to y^2 = 36ln(1+x^3), although there is uncertainty about the constant factor, with suggestions that it may actually be 4. The solution for y involves taking the square root, yielding y = ±sqrt(36ln(1+x^3) or y = ±sqrt(4ln(1+x^3)). Additionally, participants recommend expressing the solution in terms of initial conditions for clarity.

PREREQUISITES
  • Understanding of separable differential equations
  • Knowledge of integration techniques
  • Familiarity with logarithmic functions
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Review integration techniques for separable differential equations
  • Learn about initial value problems and their applications
  • Explore the properties of logarithmic functions in calculus
  • Study the implications of ± solutions in differential equations
USEFUL FOR

Students studying calculus, particularly those focusing on differential equations, as well as educators looking for examples of solving separable equations.

myusernameis
Messages
56
Reaction score
0

Homework Statement


dy/dx = (6x^2)/((1+x^3)y)


Homework Equations





The Attempt at a Solution



it's a separable func. so after integrating, it looks like this (base on my calculation)

y^2 = 36ln(1+x^3)

so how do i find y? is it just sqrt(36ln(1+x^3))

thanks
 
Physics news on Phys.org
36? Really? Could you check that again? Aside from that, sure, except y^2=A has two solutions. y=+sqrt(A) and y=-sqrt(A).
 
Dick said:
36? Really? Could you check that again? Aside from that, sure, except y^2=A has two solutions. y=+sqrt(A) and y=-sqrt(A).

is the 36 supposed to be a 4?

brain fart... suddenly forgot how to do integration..
 
Well, I got 4. Doesn't mean it's correct. If you're not sure you'd better check again.
 
I think it's 4 but also I think it's not going to matter too much when you get to the end. :wink:
 
Thanks guys!

i'm pretty sure (lol) it's 4
 
I suggest you also try writing it in the form x=
and also express both forms in terms of an initial condition e.g. xy=0 and/or yx=0.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
3
Views
2K
Replies
5
Views
1K
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K