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## Homework Statement

Solve 6x^2*y^2*dx+4x^3*y*dy=0.

## Homework Equations

This is an exact equation.

## The Attempt at a Solution

Here's my work:

6x^2*y^2*dx=-4x^3*y*dy

1/x dx=-2/3*1/y*dy

ln abs(x)+C=-2/3*ln abs(y)

1/y^(2/3)=Cx

y^(2/3)=1/(Cx)

xy^(2/3)=1/C

C=1/(xy^(2/3))

But the answer in the book says 2x^3*y^2=C. Is the book's answer correct and my answer is wrong or vice versa? Please correct me and tell me what to do if I'm wrong.