Solving Shear Stress on a Bar - Mechanics of Materials

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SUMMARY

The discussion focuses on understanding why the shearing force V does not induce shear stress (\tau_2) at point A while it does at point B in a Mechanics of Materials context. The shearing force produced by wind runs parallel to line AC, resulting in a shear stress of zero at point A due to the first moment of area Q being zero about the axis B-C. In contrast, at point B, the first moment of area Q is maximized, leading to maximum shear stress. The symmetry argument further supports that without an equal and opposite shear force, no shear stress can exist at point A.

PREREQUISITES
  • Understanding of shear stress calculations using the formula tau = VQ/(It)
  • Familiarity with the concepts of first moment of area and its significance in beam theory
  • Knowledge of Mechanics of Materials principles, particularly shear forces and stresses
  • Ability to interpret diagrams and figures from academic texts, specifically from Mechanics of Materials
NEXT STEPS
  • Study the derivation and application of the shear stress formula tau = VQ/(It)
  • Explore the concept of the first moment of area in detail and its implications in structural analysis
  • Review case studies involving shear forces in beams to solidify understanding of shear stress distribution
  • Examine additional resources on symmetry in mechanics and its effects on stress analysis
USEFUL FOR

Students and professionals in engineering, particularly those studying or working in structural and mechanical engineering, who seek to deepen their understanding of shear stress behavior in materials.

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I'm trying to understand a problem found on Mechanics of Materials and did not completely understood the problem. I can solve problems like this but I still don't know why I'm solving this way.

It is a simple question: Why the shearing force V does not cause shear stress (\tau_2) on the point A as it does on point B? (page 575 pictures c and d for reference)

Yes, I've searched on the book but did not find why

Thanks
 

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The shearing force V produced by the wind blowing on the sign runs parallel to the line AC. If we calculate the shear stress at point A using the standard formula tau = VQ/(It), then at point A, the first moment of area Q = 0 about the axis B-C, thus the shear stress = 0. We can also argue from symmetry, that if a non zero shear stress exists at point A, unless an equal and opposite shear force is present on the other side of the pole, there will be a side force introduced which is perpendicular to the shear force V, and the wind produced no such force.

It's not clear from your text if you have been introduced to calculating shear stress using the formula tau = VQ/(It). This article derives the formula for calculating shear stresses in beams:

http://www.ecourses.ou.edu/cgi-bin/ebook.cgi?topic=me&chap_sec=04.3&page=theory

At point B, the first moment of area Q about the axis B-C will be a maximum, and the shear stress at this point is also a maximum.
 

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