Solving sin²x = 1/4 in Quadrants 2, 3, and 4

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SUMMARY

The discussion focuses on solving the equation sin²x = 1/4 within the interval π/2 ≤ x < 2π, specifically in quadrants 2, 3, and 4. Participants clarify that sin²x represents the square of sin x, allowing for the application of the square root to both sides of the equation. The solutions can be derived by taking the square root of 1/4, leading to sin x = ±1/2. The relevant angles in the specified quadrants are 7π/6 and 11π/6.

PREREQUISITES
  • Understanding of trigonometric functions and their properties
  • Knowledge of the unit circle and angle measures in radians
  • Familiarity with solving equations involving squares and square roots
  • Basic grasp of the Pythagorean theorem in relation to trigonometric identities
NEXT STEPS
  • Study the unit circle to identify angles corresponding to sin x = 1/2
  • Learn about the properties of trigonometric functions in different quadrants
  • Explore the concept of inverse trigonometric functions for solving sin x equations
  • Practice solving similar trigonometric equations involving squares and roots
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Students studying trigonometry, educators teaching trigonometric identities, and anyone looking to enhance their problem-solving skills in trigonometric equations.

alpha01
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find all solutions to sin^2 x = 1/4 in pi/2 <= x < 2pi (i.e in quadrants 2,3 and 4)


i understand what i need to do but don't understand sin^2 part. will i need to apply pythagoras therom here first?



thanks
 
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\sin ^2x=(\sin x)^2

You can square root both sides, and finding x should be simple then.
 

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