Determine the quadrant(s) in which (x, y) could be located

  • Thread starter nycmathguy
  • Start date
Please omit filler like "Let me see." You don't have to write down your every thought, only those that help us understand what you're doing. "Let me see" doesn't fall into this category.You're tacitly assuming that x is nonnegative, which is false for half of the possible numbers.Same problem as above -- the point (-y, y) is in Quadrant II only if y >= 0.At least I gave it a go, right?Yes, it's good to try and work through the problem. Just be careful to only include relevant information and avoid assumptions that may not hold for all cases.
  • #1
nycmathguy
Homework Statement
Quadrants on the xy-plane.
Relevant Equations
Linear Equations
Determine the quadrant(s)
in which (x, y) could be located.
Chapter 1, Section 1.1

13. x + y = 0, x ≠ 0, y ≠ 0

Let me see.

x + y = 0

I can solve for y.

y = - x

If y is - x, we get the point (x, - x).

This leads me to see a point in quadrant 4.

I can also solve for x.

If I do so, I get x = - y.

This leads to the point (-y , y), which takes me into quadrant 2.

I say the answer is quadrants 2 and 4.

You say?
 
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  • #2
(x, -x) doesn't necessarily have to be in quadrant 4. (Should x be positive?)
 
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  • #3
nycmathguy said:
Homework Statement:: Quadrants on the xy-plane.
Relevant Equations:: Linear Equations

Determine the quadrant(s)
in which (x, y) could be located.
Chapter 1, Section 1.1

13. x + y = 0, x ≠ 0, y ≠ 0

Let me see.

x + y = 0

I can solve for y.

y = - x
This is fine. Can you draw the graph of this function?
 
  • #4
PeroK said:
This is fine. Can you draw the graph of this function?
Are you asking me to draw y = x and y = -x on the same xy-plane?
 
  • #5
nycmathguy said:
Are you asking me to draw y = x and y = -x on the same xy-plane?
Only ##y = -x##, which is the equation you have.
 
  • #6
nycmathguy said:
Homework Statement:: Quadrants on the xy-plane.
This is not a homework statement.
nycmathguy said:
Relevant Equations:: Linear Equations
Not an equation. If you can't think of any relevant equation, just leave it blank - don't just put something in for the sake of doing so.
nycmathguy said:
Determine the quadrant(s)
in which (x, y) could be located.
This is the homework or problem statement.
nycmathguy said:
Chapter 1, Section 1.1

13. x + y = 0, x ≠ 0, y ≠ 0

Let me see.
Please omit filler like "Let me see." You don't have to write down your every thought, only those that help us understand what you're doing. "Let me see" doesn't fall into this category.
nycmathguy said:
x + y = 0

I can solve for y.

y = - x

If y is - x, we get the point (x, - x).

This leads me to see a point in quadrant 4.
You're tacitly assuming that x is nonnegative, which is false for half of the possible numbers.
nycmathguy said:
I can also solve for x.

If I do so, I get x = - y.

This leads to the point (-y , y), which takes me into quadrant 2.
Same problem as above -- the point (-y, y) is in Quadrant II only if y >= 0.
nycmathguy said:
I say the answer is quadrants 2 and 4.

You say?
 
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  • #7
Mark44 said:
This is not a homework statement.
Not an equation. If you can't think of any relevant equation, just leave it blank - don't just put something in for the sake of doing so.
This is the homework or problem statement.
Please omit filler like "Let me see." You don't have to write down your every thought, only those that help us understand what you're doing. "Let me see" doesn't fall into this category.
You're tacitly assuming that x is nonnegative, which is false for half of the possible numbers.
Same problem as above -- the point (-y, y) is in Quadrant II only if y >= 0.

Can you provide an example of a HW Statement and Relevant Equations for those two categories? I have been corrected over and over and over again since joining this site.
 
  • #8
Mark44 said:
This is not a homework statement.
Not an equation. If you can't think of any relevant equation, just leave it blank - don't just put something in for the sake of doing so.
This is the homework or problem statement.
Please omit filler like "Let me see." You don't have to write down your every thought, only those that help us understand what you're doing. "Let me see" doesn't fall into this category.
You're tacitly assuming that x is nonnegative, which is false for half of the possible numbers.
Same problem as above -- the point (-y, y) is in Quadrant II only if y >= 0.
Is my answer right or wrong?
 
  • #9
nycmathguy said:
Can you provide an example of a HW Statement and Relevant Equations for those two categories?
For this thread:
Homework Statement::
Determine the quadrant(s)
in which (x, y) could be located for the line x + y = 0, x ≠ 0, y ≠ 0.

Relevant Equations::
None
nycmathguy said:
Is my answer right or wrong?
Your answer is correct -- the line is in quadrants II and IV.

In another of your threads, about the diagonals of a parallelogram, these sections might look like this:
Homework Statement::
Prove that the diagonals of a parallelogram intersect at their midpoints.

Relevant Equations::
Midpoint of the line segment from (a, b) to (c, d): ##(x_m, y_m) = (\frac{a + c}2, \frac{b + d} 2)##
 
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  • #10
nycmathguy said:
Is my answer right or wrong?
Your answer is correct, but as @Quantour pointed out in post #2, your working was not right. And, you really took a long way round. When you have: $$y = -x$$ you should see that is the equation of a straight line through the origin. To graph a straight line you need only two points. We have the origin: ##x = 0, y = 0##. We might as well take ##x = 1## for our second point, which gives ##x=1, y = -1##.

That gives us a line through the second and fourth quadrants.
 
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  • #11
PeroK said:
Your answer is correct, but as @Quantour pointed out in post #2, your working was not right. And, you really took a long way round. When you have: $$y = -x$$ you should see that is the equation of a straight line through the origin. To graph a straight line you need only two points. We have the origin: ##x = 0, y = 0##. We might as well take ##x = 1## for our second point, which gives ##x=1, y = -1##.

That gives us a line through the second and fourth quadrants.

At least I gave it a go, right?
 
  • #12
Mark44 said:
This is not a homework statement.
Not an equation. If you can't think of any relevant equation, just leave it blank - don't just put something in for the sake of doing so.
This is the homework or problem statement.
Please omit filler like "Let me see." You don't have to write down your every thought, only those that help us understand what you're doing. "Let me see" doesn't fall into this category.
You're tacitly assuming that x is nonnegative, which is false for half of the possible numbers.
Same problem as above -- the point (-y, y) is in Quadrant II only if y >= 0.
Can you please provide an example of a Homework Statement and an example of Relevant Equations for those categories?
 
  • #13
nycmathguy said:
Can you please provide an example of a Homework Statement and an example of Relevant Equations for those categories?
I already did this in post #9.
 
  • #14
Mark44 said:
I already did this in post #9.

Tale the problem about find two missing numbers.

Here it is again:

Two numbers add up to 72. One number is twice the other. Find the numbers.

The HW Statement:
Find the numbers.

What would be the Relevant Equations in this case?
 
  • #15
nycmathguy said:
Two numbers add up to 72. One number is twice the other. Find the numbers.

The HW Statement:
Find the numbers.
That's pretty vague. An improvement would be
Homework Statement::
Find two numbers whose sum is 72, with one number being twice the other.

nycmathguy said:
What would be the Relevant Equations in this case?
You could leave that section empty.
 
  • #16
Mark44 said:
You could leave that section empty.

This is what I'm talking about. Sometimes it is best to leave that section blank and for some questions it makes to complete the section.

What about for the following question?

I know how to solve the following equation. This is just an example.

Solve x + 5 = 10 for x.

Homework Statement:

Solve for x.

Relevant Equations:

Linear Equation

Is this right?
 
  • #17
nycmathguy said:
I know how to solve the following equation. This is just an example.

Solve x + 5 = 10 for x.
The line above would be a good homework statement, but this problem is soooo simple it would hardly be worth posting a question about it.
 
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  • #18
Mark44 said:
The line above would be a good homework statement, but this problem is soooo simple it would hardly be worth posting a question about it.
Moving on...
 
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1. What is meant by "quadrant" in this context?

A quadrant is a section of a coordinate plane that is divided by the x-axis and y-axis. There are four quadrants in total, labeled as I, II, III, and IV, starting in the top right and moving counter-clockwise.

2. How do I determine which quadrant a point is located in?

To determine the quadrant of a point (x, y), you need to look at the signs of the x and y values. If both x and y are positive, the point is in quadrant I. If x is negative and y is positive, the point is in quadrant II. If both x and y are negative, the point is in quadrant III. And if x is positive and y is negative, the point is in quadrant IV.

3. Can a point be located in more than one quadrant?

No, a point can only be located in one quadrant at a time. Each quadrant is a distinct section of the coordinate plane.

4. How does determining the quadrant of a point help in graphing?

Determining the quadrant of a point can help you accurately plot the point on a graph. It also helps you understand the relationship between the x and y values of the point, as well as its position relative to the origin.

5. Is there a specific order in which the quadrants are labeled?

Yes, the quadrants are labeled in a counter-clockwise direction, starting with quadrant I in the top right corner and moving to quadrant IV in the bottom right.

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