Solving Soccer Ball Kinematics: Max Height & Vertical Velocity

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SUMMARY

The discussion focuses on solving kinematic equations related to a soccer ball kicked with an initial velocity of 25 meters per second at a 40-degree angle. The vertical component of the initial velocity is calculated using the formula Viy = 25 * sin(40 degrees), resulting in approximately 16.14 meters per second. To find the maximum height, the equation dy = (Viy^2) / (2 * g) is utilized, where g is the acceleration due to gravity (approximately 9.81 m/s²). The sketch of the ball's height over time should depict a parabolic trajectory, starting from the initial position, reaching the maximum height, and returning to the ground level.

PREREQUISITES
  • Understanding of basic kinematics
  • Knowledge of trigonometric functions, specifically sine
  • Familiarity with gravitational acceleration (g = 9.81 m/s²)
  • Ability to sketch parabolic trajectories
NEXT STEPS
  • Learn how to derive kinematic equations for projectile motion
  • Study the concept of maximum height in projectile motion
  • Explore the use of graphing tools to visualize projectile trajectories
  • Investigate the effects of air resistance on projectile motion
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding projectile motion and its applications in sports.

zelda1850
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someone please help me with my homework !

Homework Statement



A kicked soccer ball has an initial velocity of 25 meters per second at an angle of 40 degrees above the horizontal level ground [neglect friction]

A)calculate the magnitude of the vertical component of the balls initial velocity

b) calculate the maximum height of the ball reaches above its initial speed

c) sketch the balls height from the its initial position at point p until it returns to level ground

Homework Equations



A) Viy sin 40 degrees

B) dy= vytrise is this the correct equation?

c) I am not sure how i can sketch it yet

The Attempt at a Solution



im confused with the 2nd problem how can i find maximum height if somoene can explain to me that wll help a lot ^-^
 
Last edited:
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At the maximum height, the instantaneous vertical velocity of the ball must be zero.
 
so the vertical velocity is zero?
 

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