Solving Sound Interference: Phase Difference of Waves at 4.40m & 4.00m

[affans]

Homework Statement

Two sound waves, from different sources with the same frequency, 540 Hz, travel in the same direction at 330m/s. The sources are in phase. What is the phase difference of the waves at a point that is 4.40 m from one source and 4.00 from the other.

Homework Equations

We know that \Phi = \DeltaL / wavelength * (2pi)
We also know when the delta L / wavelentgh is a positive integer value, fully constructive interference occurs.

If delta L/ wavelength is odd integer value then fully destructive interference occurs.

and then you have your regular kinematics, and dynamics eqns.

The Attempt at a Solution

f = 540 Hz, velocity = 330m/s
f\lambda = velocity
and we solve for lamda = 540/330 = 1.64 m

now we plug that into the phase eqn.

\Phi = \frac{0.40}{1.64}

that is equal to 0.2439024...

now i don't know that's my answer, or should i multiply it by 2pi . or what?

 

[queenofbabes]

"We know that \Phi = \DeltaL / wavelength * (2pi)"

"\Phi = \frac{0.40}{1.64}"

You're missing the 2pi.