- #1

thatguy4000

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## Homework Statement

A. Two identical speakers, with the same phase constant, are arranged along a 1D track. One speaker remains at the origin. The other speaker can slide along the track to any position x. You are on the track at x=10

**m**. You hear interference maxima when the adjutable speaker's position is 0.6

**m**and 1.2

**m**and at no points in between. What is the frequency of the sound from the speakers in

**Hz**?

B. The speakers are now allowed to have different phase constants. They are adjusted so that you hear interference maxima when the adjustable speaker is at x = 0.6

**m**and again when it is at x = 1.05

**m**. What is the difference in the phase constant between the two speakers in

**rad**?

## Homework Equations

velocity = wavelength * frequency

delta phi = phi2 - phi1 = (2pi * delta x)/wavelength

## The Attempt at a Solution

The wavelength in part A would be 0.6m because that's the distance between the maximum interference, giving me frequency = 343m/s / 0.6m = 571.67Hz (correct).

I could not get B correctly though. Using the difference in phase constant equation, delta phi (phase difference) = (2pi * 0.45m) / 0.6m = 4.71 radians (wrong). What did I do wrong?