Solving Spring Oscillations Homework: Stretched Distance d

Click For Summary
SUMMARY

The discussion revolves around calculating the stretched distance (d) of a spring when a mass of 0.35 kg is attached. The participant calculated the period (T) to be approximately 0.489 seconds based on 100 oscillations in 48.9 seconds. Using the formula T = 2π(√(m/k)), they determined the spring constant (k) to be 3.45 N/m. However, the calculated distance was approximately 1 meter, while the correct answer provided by the teacher is 5.94 cm, indicating a miscalculation in the application of the formulas.

PREREQUISITES
  • Understanding of harmonic motion and oscillations
  • Familiarity with Hooke's Law (F = kx)
  • Knowledge of the relationship between period and frequency
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review the derivation of the formula for the period of a mass-spring system
  • Learn about the implications of spring constant (k) in oscillatory motion
  • Study the effects of mass on the oscillation frequency
  • Explore common mistakes in calculations involving oscillations and springs
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators looking for examples of common calculation errors in spring dynamics.

sheepy
Messages
10
Reaction score
0

Homework Statement


When a mass of 0.35 kg is attached to a vertical spring and lowered slowly, the spring stretches a distance of d. The mass is now displaced from its equilibrium position and undergoes 100 oscillations in 48.9 seconds. WHat is the stretched distance d?

Homework Equations


Number of oscillations/Time = Period (T)
T = 2pi ([tex]\sqrt{m/k}[/tex])
F=kx

The Attempt at a Solution


I found by doing 100/48.9, the period is around 2 oscillations per second.
Using the second equation I figured out that k=3.45 by plugging it all the other variables. Then i know that the F=mg. So mg is 3.43.
3.43/3.45 = x (distance)
The distance comes out to around 1. But my teacher says that 5.94 cm...what did i do wrong?
 
Physics news on Phys.org
the period is supposed to be 48.9/100 s
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
6
Views
1K
Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
1K
Replies
1
Views
2K
Replies
19
Views
2K
Replies
9
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K