Solving Spring Problem w/ Mass of 65.0kg & Force of 775N

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SUMMARY

The discussion centers on calculating the potential energy of a spring when a mass of 65.0 kg is suspended from it under a force of 775 N. The spring constant (k) was determined to be 3875 N/m using Hooke's Law. The key challenge is accurately calculating the additional stretch of the spring due to the gravitational force acting on the mass. The correct approach involves equating the gravitational potential energy to the elastic potential energy and using the formula for elastic potential energy to find the total energy stored in the spring.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Knowledge of gravitational potential energy calculations
  • Familiarity with elastic potential energy formulas
  • Ability to draw and interpret free body diagrams
NEXT STEPS
  • Calculate the total stretch of the spring using the weight of the mass and Hooke's Law
  • Explore the formula for elastic potential energy: PE = 0.5 * k * x²
  • Review the principles of conservation of energy in mechanical systems
  • Practice drawing free body diagrams for systems involving springs and weights
USEFUL FOR

Students studying physics, engineers working with mechanical systems, and anyone interested in understanding spring dynamics and energy calculations.

dagger32
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ok, maybe i am missing something here with this problem and it is probably really simple, but here it is:

A force of 775N stretches a certain spring a distance of 0.200m. What is the potential energy of the spring when a mass of 65.0kg hangs vertically from it?

I have tried conservation of energy laws, figuring that the total potential energy of the system is elastic energy + grav. potential energy. I have tried equatng gravtational potential energy to elastic potential energy, which has gotten me nowhere.

My first step was to find k, the spring constant, which I got to be 3875 using Hooke's Law. Yet, the biggest problem I am having is trying to calculate the distance the spring will stretch with this mass. .2 m is not correct because the spring should have a longer distance due to gravity. Hence, i was trying to equate grav. potential energy and elastic potential energy.

I think I am just completely missing something or misinterpreting the problem.
 
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ok draw a free body diagram of the mass hanging from the spring and see your FORCES involved and not the energies, yet

How much is the spring stretched by when the mass is hanging?

Can you calculate the energy stored in the spring given the stretch of the spring?
 
a little drawing goes a long way. Just had to use the force of weight, find the distance using hookes law, and throw that into the elastic potential energy formula.

Thanks! :smile:
 

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