MHB Solving Square Root Questions: A Math Tutorial for Beginners

AI Thread Summary
The discussion focuses on solving the square root of the expression involving 13^2 - 12^2. A key error identified is that the square root does not cancel out with the difference of squares, and the correct calculation shows that 13^2 equals 169, not 149. The correct simplification leads to √(169 - 144) = √25, which equals 5. Participants clarify that it's acceptable to simplify √25 to 5, emphasizing the importance of accurate arithmetic in such problems. Overall, the conversation highlights common misunderstandings in basic math operations and encourages careful calculation.
OMGMathPLS
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How does this work? (Also, I am very math illiterate and do not understand even the most basic terms, if you could kindly speak as you would to a child I would GREATLY appreciate it.)

sq rt sign over 13^2 - 12^2 (over both of it together)

Now the answer is 5, because

(13)(13) - (12)(12)

149-144 = 5

But what canceled out the sq rtt? We did the exponents so did that cancel it out?

Thanks for help.

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Several of your steps are invalid.

1) $\sqrt{a^2 - b^2} \neq a - b$, i.e., the square root and the difference of squares do not "cancel out". For example, let $a = 5$ and $b = 4$. $a^2 - b^2 = 5^2 - 4^2 = 25 - 16 = 9$ and $\sqrt{5^2-4^2} = \sqrt{9} = 3$ whereas $4 - 3 = 1$.

2) What you wrote in the attachment was $\sqrt{13^2 - 12^2} = 13^2 - 12^2$. Where did the square root go? This is an invalid step.

3) $13^2 = 13 \times 13$ is actually $169$, not $149$. So your calculations are void.

Can you recalculate the expression now that your have been pointed out?
 
OMGMathPLS said:
How does this work? (Also, I am very math illiterate and do not understand even the most basic terms, if you could kindly speak as you would to a child I would GREATLY appreciate it.)

sq rt sign over 13^2 - 12^2 (over both of it together)

Now the answer is 5, because

(13)(13) - (12)(12)

149-144 = 5

But what canceled out the sq rtt? We did the exponents so did that cancel it out?

Thanks for help.

View attachment 3248

You have a mistake at your calculation.
It is $13^2=169$ instead of $149$.

Therefore, $$\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5$$
 
Oh. Well I guess that explains it then. God!

Ok, so you leave the sq rt then at 25 but it's ok to put it back to 5?
 
Ok, so you leave the sq rt then at 25 but it's ok to put it back to 5?

Note that $25 = 5^2$. Thus, by commutativity,

$$\sqrt{25} = \sqrt{5^2} = \sqrt{5}^2 = 5$$
 
OMGMathPLS said:
Oh. Well I guess that explains it then. God!

Ok, so you leave the sq rt then at 25 but it's ok to put it back to 5?

Since $5\cdot 5=25 \Rightarrow 5^2=25$ we have that $ \sqrt{5^2}=\sqrt{25}\Rightarrow 5=\sqrt{25}$
 
mathbalarka said:
Several of your steps are invalid.

1) $\sqrt{a^2 - b^2} \neq a - b$, i.e., the square root and the difference of squares do not "cancel out". For example, let $a = 5$ and $b = 4$. $a^2 - b^2 = 5^2 - 4^2 = 25 - 16 = 9$ and $\sqrt{5^2-4^2} = \sqrt{9} = 3$ whereas $4 - 3 = 1$.

2) What you wrote in the attachment was $\sqrt{13^2 - 12^2} = 13^2 - 12^2$. Where did the square root go? This is an invalid step.

3) $13^2 = 13 \times 13$ is actually $169$, not $149$. So your calculations are void.

Can you recalculate the expression now that your have been pointed out?

OMGMathPLS said:
Oh. Well I guess that explains it then. God!

Ok, so you leave the sq rt then at 25 but it's ok to put it back to 5?
He was really only trying to help without giving direct answers (Blush)
 
ineedhelpnow said:
He was really only trying to help without giving direct answers (Blush)
Yeah, thanks for the help. It's just embarrassing. I really thought I partially figured it out. So they explained the arithmetic error and it's ok to solve it all the way to a 5 not simplify. Just a dumb mistake I made and I'm praying it won't kill me later. Thanks.
 
You can do this problem in this manner also
Hint: a^2-b^2 =(a+b)(a-b)
13^2-12^2=(13+12)(13-12)
=25*1
 
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