Solving Statics Problem: 6-kg Plank, Forces at A & B

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SUMMARY

The discussion centers on calculating the forces acting on a 6-kg uniform plank supported at two points, A and B. The weight of the plank is determined using the equation w=mg, resulting in a downward force of 58.9 N at point A. The upward force at point B is the sum of the weight and any additional forces acting on the plank, which requires further analysis to confirm. A sketch illustrating the forces and angles is suggested for clarity.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with basic physics equations, specifically w=mg and M=fd
  • Knowledge of free body diagrams
  • Ability to perform vector resolution of forces
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  • Study static equilibrium problems involving multiple forces
  • Learn how to create and analyze free body diagrams
  • Explore the concept of torque and its application in static systems
  • Review examples of force calculations in uniform beams
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Students studying physics, particularly those focusing on mechanics and static equilibrium, as well as educators seeking to enhance their teaching of force analysis in structures.

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Homework Statement



A man holds a 6-kg uniform plank. Determine forces at A and B. A is at 1 end of the board and B is 0.6 metres further down. total length is 1.4 m

Homework Equations



w=mg
M=fd

The Attempt at a Solution



there will be a force down at A and up at B. i think A will just be weight. So 58.9 N not sure about B though.
 
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i think i might have it. A is down so is weight so B is just these two added together?
 
need a sketch showing angles etc.
 

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