Solving Statics Vectors: 10N Weight, 30° Support Angle

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Homework Help Overview

The problem involves a weight of 10 N suspended from a three-legged support system, where the legs form equal angles with each other and with the rope. The objective is to determine the forces in the legs, given that they form a 30-degree angle with the rope.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses confusion regarding the problem and their attempts at using equilibrium equations. They question whether the forces in the legs are equal and express uncertainty about their calculations involving projections.
  • Some participants confirm that the forces in the legs should be equal due to symmetry and suggest focusing on vertical components. Others question the original poster's use of projections and the role of a specific force in their analysis.
  • One participant suggests isolating one leg as a free body to clarify the forces acting on it and to simplify the equilibrium analysis.

Discussion Status

The discussion is ongoing, with participants providing guidance on the symmetry of the forces and suggesting methods to approach the problem. There is a focus on clarifying assumptions and interpretations, particularly regarding the equal forces in the legs and the use of free body diagrams.

Contextual Notes

The original poster expresses significant difficulty with the topic of statics, indicating a potential lack of confidence in their understanding of the material. There is an emphasis on ensuring all forces are included in the analysis, and the original poster's mention of projections raises questions about their relevance in this context.

starryeyed
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Homework Statement



A weight of 10 N is hanging from the top of a three-legged support. The legs are attached to the horizontal floor and form equal angles with each other. Find the forces in the legs, if they form an angle of 30 degrees with the rope.


Homework Equations


\sumFx=0
\sumFy=0
\sumFz=0

The Attempt at a Solution


I'm lost. Maybe I should just give up on the whole topic of statics, I've never had this much difficulty with any other subject in physics. I understand the examples and the stuff in the book but I can't seem to solve any problems on my own. I'm not sure if these are even correct. Sum of the projections of the vectors-
BAsin30+BCsin30+BDsin30=0 The projections of P and BE are zero, since they are at a 90 degree angle with x.
BAcos30+BCcos30+BDcos30+BE+10=0
BAcos15+BCcos15+BDcos15+BEcos45+10cos45=0
The 15 is there, because I figured they were at a 15 degree angle with z.
I don't know if BA, BC and BD are all supposed to be equal:S
Anyways, help would be very much appreciated:)
 

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Yes, they are all the same.
 
Hi starryeyed! :smile:
starryeyed said:
A weight of 10 N is hanging from the top of a three-legged support. The legs are attached to the horizontal floor and form equal angles with each other. Find the forces in the legs, if they form an angle of 30 degrees with the rope.

I don't know if BA, BC and BD are all supposed to be equal:S

Yes, of course they're supposed to be equal … don't be paranoid!

From symmetry, the forces will obviously be equal, and since they're equal, any horizontal component will be zero …

so just take the vertical components

(which I think you've done, but I don't understand what BE is supposed to be :redface:)

(and why are you talking about projections? :confused:)
 
If you isolate one leg as a free body and put all the forces acting on it, and then make an equilibrium statement about it, the answer will appear more easy. Isolating one leg implies a downward force at its top of P/3. Don't forget you must put ALL the forces on the free body diagram.
 

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