How to Solve a Space Truss Statics Problem with Ball and Socket Supports?

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SUMMARY

The discussion focuses on solving a space truss statics problem involving a telescope mirror housing supported by six bars with ball and socket supports. The total mass is 3000 kg, with the center of mass at point G. The force vector P is defined as P=(30*cos(20)cos(60), -30cos(20)sin(60), -30sin(20))[kN]. The user attempts to apply static equilibrium equations but struggles with the number of unknowns compared to the equations available. The suggestion is made to use the tensions in the six links as unknowns, which would provide a solvable system of six equations.

PREREQUISITES
  • Understanding of static equilibrium equations (∑Fx=0, ∑Fy=0, ∑Fz=0)
  • Familiarity with vector forces and their components
  • Knowledge of ball and socket support mechanics
  • Basic principles of truss analysis and geometry
NEXT STEPS
  • Learn about finite element modeling for complex geometries
  • Study the method of joints in truss analysis
  • Explore the concept of reaction forces in ball and socket supports
  • Investigate the use of symmetry in solving statics problems
USEFUL FOR

Students and professionals in engineering, particularly those focusing on structural analysis, statics, and mechanics of materials. This discussion is beneficial for anyone tackling complex truss problems involving multiple supports and forces.

LucasSG
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Homework Statement


A telescope mirror housing is supported by 6 bars in form of a space truss with geometry defined by the figure below. The total mass is 3000[kg] with center of mass being point G. The distance between:
z axis and points A, B and C is 1 [m]
z axis and points D, E and F is 2.5[m]
76f3a2e2aca3612136545f2b2f4eeb84.png


Using the exact same coordinate system the problem gives, the points coordinates are:
G=(0,0,1)
A=(-1/2, √3/2, 0)
B=(-1/2, -√3/2, 0)
C=(1,0,0)
D=(-5/2, 0, -4)
E=(5/4, (-5√3)/4, -4)
F=(5/4, (5√3)/4, -4)

The force vector P is equal to:
P=(30*cos(20)cos(60), -30cos(20)sin(60), -30sin(20))[kN] (using g=10m/s²)(Ball and socket supports)
26f43ff721f9354d1e8a04b91c07d196.png


Homework Equations


∑Fx=0 (1)
∑Fy=0 (2)
∑Fz=0 (3)
∑Mx=0 (4)
∑My=0 (5)
∑Mz=0 (6)

The Attempt at a Solution



First thing i thought was to consider A, B and C "ball and socket supports" detaching them from the bars. So i would have reactions on x, y and z directions in each of these three points. Then i would consider the entire part between G and the points A, B and C to be a rigid body. The forces that act on each point would be (using the same coordinate system the problem gives me):
Fa=(Fax, Fay, Faz) [kN]
Fb=(Fbx, Fby, Fbz) [kN]
Fc=(Fcx, Fcy, Fcz) [kN]
P=(30*cos(20)cos(60), -30cos(20)sin(60), -30sin(20))[kN]
Then i used ∑M=0 on point A, so i got:
∑Ma= AB x Fb +Ac x Fc + AG x P = 0
= (-√3Fbz, 0, √3Fbx) + (-0.86Fcz, -1.5Fcz, 0.86Fcx + 1.5Fcy) + (15√3*(cos(20)+sin(20)), 15cos(20), 15sin(20)) And that's where I'm stuck. Using equations 1-6 now i got 6 equations and 9 unknowns, i guess now i need to find symmetry between the forces on those 3 points, but i can't seem to find any new information about those forces that can help me get the other 3 equations i need.

I suppose finding the sum of the moments on points B or C won't give me any new information.

Am i trying to solve this problem the right way or there's a better way of finding the reactions on A, B and C to analyze the truss? If so, what can i do next? I'm really stuck right now...
 
Last edited:
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Each ball and socket is connected to only two links, so you don't have three independent component of each reaction force. The reaction force can only lie in the plane containing the two links.

Probably the best choice of unknowns are the tensions in the 6 links. That way, you have 6 equations in 6 unknowns.

(But solving a problem with the geometry as messy as this by hand seems rather pointless, compared with setting up a simple finite element model...)
 

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