Solving system of equations for matrix?

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SUMMARY

The discussion focuses on solving the homogeneous system of equations represented by the matrix equation Bx = 0, where B is a 3x2 matrix: [5 -1; 2 2; 1 4]. The user attempts to find the reduced row echelon form (RREF) of the augmented matrix [5 -1 | 0; 2 2 | 0; 1 4 | 0], resulting in RREF: [1 0 | 0; 0 1 | 0; 0 0 | 0]. The conclusion drawn is that the only solution is the trivial solution x = (0, 0), which is indeed correct, as it satisfies the equation Bx = 0.

PREREQUISITES
  • Understanding of matrix operations and linear algebra concepts
  • Familiarity with reduced row echelon form (RREF)
  • Knowledge of homogeneous systems of equations
  • Basic proficiency in matrix multiplication
NEXT STEPS
  • Study the properties of homogeneous systems of equations
  • Learn about the implications of the trivial solution in linear algebra
  • Explore the concept of null space and its relation to matrix equations
  • Practice solving systems of equations using different matrices and methods
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Students studying linear algebra, educators teaching matrix theory, and anyone interested in solving systems of equations using matrix methods.

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Homework Statement



Solve the system of equations for Bx = 0.

Where B is the following matrix:
[ 5 -1 ]
[ 2 2 ]
[ 1 4 ]

and the x is some vector I am assuming.. is it:
[ x1 ]
[ x2 ]

Homework Equations



The Attempt at a Solution



So what I figured was that I should do this:

[ 5 -1 | 0 ]
[ 2 2 | 0 ]
[ 1 4 | 0 ]

Is this correct? Then if I get it to rref

[ 1 0 | 0 ]
[ 0 1 | 0 ]
[ 0 0 | 0 ]

What do I do now? Is x1 = 0 and x2 = 0?

That seems like it's incorrect so I was wondering if someone can check over for me and offer any help? Thank you! :)
 
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Why do you think it's incorrect? You can check your work, you know. What do you get when you multiply
\left[\begin{array}{c c}5&amp;-1\\2&amp;2\\1&amp;4\end{array}\right]<br /> \left[\begin{array}{c}0\\0\end{array}\right]
What should you get?
 
Last edited:
Mark44 said:
Why do you think it's incorrect? You can check your work, you know. What do you get when you multiply
\left[\begin{array}{c c}5&amp;-1\\2&amp;2\\1&amp;4\end{array}\right]<br /> \left[\begin{array}{c}0\\0\end{array}\right]
What should you get?

Won't that give me a zero matrix? How would that help solve the system??
Sorry if I'm asking such stupid questions but it's been a long week..
 
The problem was to find an x such that Bx= 0. You have found that x= (0, 0) is the only such x. What is wrong with that?
 

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