Solving the differential equation m(dv/dt)=mg-bv^n

[Opressor]

m (dv / dt) = mg-bvⁿ

 

[kuruman]

m(d²v/dt²)=-mg-bvⁿ

This equation doesn't make sense if the symbols have their usual meanings. Did you mean m(dv/dt)=-mg-bvⁿ ?

 

[scottdave]

What does it represent? It is a differential equation (second derivative of velocity?) equals -(mass)(gravity?) - (some number b) times (velocity?)^n
If I am even close, it does not look like the dimensions match.

 

[Opressor]

is the equation of a falling body having as resistance force bv ^ n

 

[DaveE]

It looks like you are asking about solutions to dx/dt = 1 - axⁿ? For a and n = constants you can just integrate it, so I guess there is more to your equation than we understand?