Solving the Particle Velocity at Time t=5

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Homework Help Overview

The problem involves determining the velocity of a particle with a mass of 1 kg under the influence of a force defined as F=6(i+t j) N, specifically at time t=5 seconds. The context is rooted in classical mechanics, focusing on the relationship between force, mass, and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the velocity from the given force using Newton's second law and integration. Some participants question the clarity of the constants used in the integration process and suggest that different letters could be used for the integration constants to avoid confusion.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's approach. While some affirm the correctness of the calculations, others offer suggestions for improvement in clarity and notation. There is no explicit consensus on the final form of the answer, as different aspects of the solution are being explored.

Contextual Notes

Participants note the importance of recognizing that the integration constants may differ for each component of the velocity vector. Additionally, there is a mention of the need to consider both magnitude and direction when discussing velocity as a vector quantity.

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Homework Statement



At time , t s , a particle with a mass 1 kg moves under the action of force F=6(i+t j) N. If the particles starts to move at time t=0 ,find the velocity of the particle at t=5 .


Homework Equations





The Attempt at a Solution



By F=ma

the acceleration vector , a = 6i+6t j

integrate this gives , v= (6t+c)i+(3t^2+c)j

and when t=0 , v=0

therefore , v=(6t)i+(3t^2)j

and at t=5 s, v=(30)i+(75)j and my next job is to find its magnitude

Is everything all right ?
 
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Yes that looks to be correct, although you can leave your answer in the vectro form v=30i+75j. If you just put the magnitude, you'd need to put the angle as well since velocity is a vector quantity in that it has both magnitude and direction.
 
Just a tiny comment... you write F = ma and then write down a at once. You have used that the mass is equal to 1 here, you might have mentioned that more explicitly, perhaps.

Also the integrations are independent, so the "+ c" that goes with the i-component is not necessarily the same as the "+ c" in the j-component. You would better use different letters for those, for example

v= (6t+c1)i+(3t^2+c2)j
Then from v(t = 0) = 0 (= 0 i + 0 j) it indeed follows that c1 = c2 = 0 (but in general, you can get different constants).

Just some nitpicking from my side though, because you did correctly solve the problem.
 
thank you !
 

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