Solving the Physics Problem: Object Thrown Upward with Initial Speed of 8 m/s

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SUMMARY

The discussion centers on solving a physics problem involving an object thrown upward with an initial speed of 8 m/s and a total flight time of 3 seconds. The object, with a mass of 0.5 kg, is analyzed under the assumption of neglecting air resistance. The key question is to determine the height from which the object was thrown, emphasizing the application of kinematic equations in physics.

PREREQUISITES
  • Kinematic equations of motion
  • Understanding of projectile motion
  • Basic algebra for solving equations
  • Concept of gravitational acceleration (9.81 m/s²)
NEXT STEPS
  • Study the derivation and application of the kinematic equation: h = v_i * t + 0.5 * g * t²
  • Learn about the effects of gravity on projectile motion
  • Explore examples of vertical motion problems in physics
  • Review concepts related to free fall and maximum height calculations
USEFUL FOR

Students learning physics, educators seeking to explain projectile motion, and anyone interested in solving real-world physics problems involving vertical motion.

etsie7538
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How do you solve this problem?

An object of mass 0.5 kg is thrown straight upward with an initial speed of 8 m/s. Its total flight time - from release to impact - is 3s. From what height was the object thrown? (Ignore effects due to the air.)


I am not a physics student. I am a virologist who is trying to learn general physics for tutoring purposes. Just thought this would be a good place to post. Thanks!
 
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I think you're looking for the homework help forums.
 
Yes I can solve it but this sounds like homework so what have you tried so far?
 
Sorry, guys, I just read the post about homework. I will post there instead.
 
i'm confused... so the object was thrown upward, flew for 3 seconds and then hit something ?
 
Johannes said:
i'm confused... so the object was thrown upward, flew for 3 seconds and then hit something ?

Yes … it hit the physics student who threw it … on the head! :biggrin:
 

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