The speed which a ball must be thrown to reach 8m.

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Homework Help Overview

The problem involves calculating the initial speed required for a ball of mass 0.2 kg to reach a height of 8.0 m when thrown vertically upwards. The discussion centers around the application of kinematic equations and the effects of gravitational acceleration.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the use of the equation Vf² - Vo² = 2gH, questioning the signs and values used for gravitational acceleration and final velocity.

Discussion Status

There is an ongoing examination of the calculations, particularly regarding the signs of the variables and the interpretation of the results. Some participants have provided clarifications about the correct use of gravitational acceleration and the importance of unit consistency in the calculations.

Contextual Notes

Participants are discussing the assumption of no air resistance and the implications of using positive versus negative values for gravitational acceleration in their calculations.

Meezus
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Homework Statement



An object of mass 0.2 kg is thrown vertically upwards from ground level and reaches a height of 8.0 m. Calculate: the speed with which it must be thrown.

Homework Equations



Vf2 – Vo2 = 2gH

The Attempt at a Solution



Vf2 – Vo2 = 2gH
Vf = Final Velocity = 0 (Ball at maximum height)
Vo = Initial Velocity.
g = 9.8
H =8m
0 - Vo2 = 2 x -9.8 x 8 = -156.8

This is my attempt so far but I'm getting a negative answer, can anyone show me where I'm going wrong?
 
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Suggesting there is no air resistance ( no loss of energy ):

½*m*V02 = m*g*H →

V02 = 2*g*H

or you could say:

V02 – Vf2 = 2*g*H ( Vf = 0 ).
 
Hesch said:
Suggesting there is no air resistance ( no loss of energy ):

½*m*V02 = m*g*H →

V02 = 2*g*H

or you could say:

V02 – Vf2 = 2*g*H ( Vf = 0 ).

This is what I'm already doing but getting a negative number? Should I just be times by 9.8 not -9.8?
 
No, I have switched the order of velocities, V0 and Vf .
This will change the sign of the result.
 
And you should use g = +9.8 m/s2.
Otherwise the potential energy will be negative.
 
Hesch said:
And you should use g = +9.8.
Otherwise the potential energy will be negative.

so V02 – Vf2 = 2*g*H ( Vf = 0 ).
0 - Vf2 = 2 x 9.8 x 8 = 156.8.

is this correct?
 
No, your first line is correct, but the second is not.

V02 is not equal to 0.
 
Hesch said:
No, your first line is correct, but the second is not.

V02 is not equal to 0.

V02 = 2*g*H

so V02= 2 x 9.8 x 8 = 156.8
 
Yes.

Remember units!
 
  • #10
Hesch said:
Yes.

Remember units!

156.8 m/s correct?
and thank you
 
  • #11
No, try to insert units in this calculation:

2 x 9.8 x 8 = 156.8

Will the unit of the result be m/s? Or will it be m2/s2?
Why?
 
  • #12
V02 = 2 × 9.8 [m/s2] × 8 [m] = 156.8 [m2/s2] →
V0 = √(156.8 [m2/s2]) = 12.52 [m/s]

Always check the units. Then you can see if something is wrong in your calculation.
Here the square root was missing.
 
  • #13
Hesch said:
V02 = 2 × 9.8 [m/s2] × 8 [m] = 156.8 [m2/s2] →
V0 = √(156.8 [m2/s2]) = 12.52 [m/s]

Always check the units. Then you can see if something is wrong in your calculation.
Here the square root was missing.
Thank you for all your help :) it is greatly appreciated
 

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