Solving the Poppy Seed and Sand Diameter Puzzle

  • Context: High School 
  • Thread starter Thread starter ronaldor9
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Discussion Overview

The discussion revolves around calculating the diameter of grains of sand contained within a spherical poppy seed, which is stated to be 0.5 mm in diameter. Participants are examining the mathematical approach to this problem and questioning the accuracy of a provided answer from a book.

Discussion Character

  • Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant presents a calculation of the volume of the poppy seed assuming it is spherical, leading to a derived volume for each grain of sand.
  • Another participant agrees with the calculated diameter of the sand grain based on the volume derived, suggesting the book's answer is incorrect.
  • A different viewpoint suggests that the discrepancy between the calculated diameter and the book's answer could be attributed to rounding errors rather than a fundamental error in the calculations.

Areas of Agreement / Disagreement

Participants express disagreement regarding the accuracy of the book's answer, with some supporting the calculated value while others suggest the difference may not be significant.

Contextual Notes

Assumptions include the spherical shape of the poppy seed and the uniformity of the grains of sand. The discussion does not resolve the potential impact of rounding errors on the final answer.

ronaldor9
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Suppose a poppy seed is .5 mm in diameter and holds ten thousand grains of sand. Find the diameter of each grain of sand? I am reading this book and the stated answer seems wrong.
thanks
 
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Assuming the poppy seed to be spherical, its volume is given by:

[tex]V_p=\frac{\pi}{6}d^3=\frac{\pi}{6}(0.5\times 10^{-3})=6.5\times 10^{-11}\text{m}^3[/tex]

The volume of a grain of sand is given by:

[tex]V_s=\frac{V_p}{10000}=\frac{6.5\times 10^{-11}}{10000}=6.5\times 10^{-15}\text{m}^3[/tex]

The diameter of a grain of sand is given by:

[tex]d_s=\sqrt[3]{\frac{6V_s}{\pi}}=2.3\times 10^{-5}\text{m}[/tex]
 
yeah that's what I've been geting, the book is wrong it had it as 0.025 mm!
 
They are the same order of magnitude, the difference could just be due to rounding errors
 

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