Solving the Standard Potential of NO in Alkaline Medium

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The standard reduction potential of NO to N2O in alkaline medium at 298K is being calculated, starting from the known potential of 1.59V in acidic conditions. The user attempts to derive the potential in alkaline conditions by manipulating the equations, but encounters an error in their calculations. They reverse the reaction and apply the Nernst equation but find their result inconsistent. The discussion highlights the need for clarification on the correct approach to calculate the standard potential in alkaline medium. Assistance is requested to resolve the confusion in the calculations.
Krushnaraj Pandya
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Homework Statement


in acid medium the standard reduction potential of NO converted to N2O is 1.59V .its standard potential in alkaline meduim at 298k would be?

Homework Equations


a)2NO+2H ---> N2O +H20 E=1.59
b)2NO + H2O ---->N2O + 2OH- E=x
c)2H2O---->2H+ + 2OH- E=0.826 (calculated, correct and verified)

The Attempt at a Solution


Reversing b) we get E= -x
adding a and reversed b, we get reversed c. Therefore 1.59-x=-0.826, so x should be 1.59+0.826 but this is incorrect. Where am I wrong? any help would be appreciated.
 
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I just became a member on chemical forums. It seems to have a more active chemistry community than PF but I wonder why their interface isn't as uncluttered and intuitive as here
 
Also,Thanks a lot for the help :D
 

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