Solving the Standard Potential of NO in Alkaline Medium

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Discussion Overview

The discussion revolves around determining the standard reduction potential of nitric oxide (NO) in alkaline medium, specifically comparing it to its known potential in acidic medium. The context is primarily homework-related, focusing on electrochemical equations and their implications.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • The standard reduction potential of NO to N2O in acidic medium is stated as 1.59V.
  • A proposed reaction in alkaline medium is presented, with an unknown standard potential denoted as E=x.
  • The participant attempts to derive the value of x by manipulating the equations but expresses uncertainty about the correctness of their approach.
  • Another participant mentions a different forum, suggesting an interest in community engagement rather than contributing to the technical discussion.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to find the standard potential in alkaline medium, and the discussion remains unresolved regarding the participant's calculations.

Contextual Notes

The discussion lacks clarity on the assumptions made in the calculations and does not address potential dependencies on specific definitions or conditions in electrochemistry.

Krushnaraj Pandya
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Homework Statement


in acid medium the standard reduction potential of NO converted to N2O is 1.59V .its standard potential in alkaline meduim at 298k would be?

Homework Equations


a)2NO+2H ---> N2O +H20 E=1.59
b)2NO + H2O ---->N2O + 2OH- E=x
c)2H2O---->2H+ + 2OH- E=0.826 (calculated, correct and verified)

The Attempt at a Solution


Reversing b) we get E= -x
adding a and reversed b, we get reversed c. Therefore 1.59-x=-0.826, so x should be 1.59+0.826 but this is incorrect. Where am I wrong? any help would be appreciated.
 
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I just became a member on chemical forums. It seems to have a more active chemistry community than PF but I wonder why their interface isn't as uncluttered and intuitive as here
 
Also,Thanks a lot for the help :D
 

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