Solving the Vertical Throwing Object on Moon vs Earth Gravity

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Homework Help Overview

The discussion revolves around the problem of determining how much higher an object thrown vertically upward on the Moon will go compared to the same object thrown on Earth, given the same initial velocity. The context involves understanding gravitational acceleration differences between the two celestial bodies.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between initial velocity and maximum height, with some suggesting specific values for initial velocity to simplify calculations. Questions about kinematic formulas and their application are raised, along with requests for guidance on how to derive the height mathematically.

Discussion Status

The discussion is active, with participants sharing thoughts on the problem and attempting to clarify concepts. Some guidance has been offered regarding the use of kinematic equations, but no consensus has been reached on the specific methods to solve the problem. Participants express a need for formulas and further clarification on the calculations involved.

Contextual Notes

Participants mention constraints such as not having access to textbooks or formulas, indicating that this is a homework assignment over the summer. There is also a focus on understanding the reasoning behind the relationships between variables rather than just obtaining a numerical answer.

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If an object is thrown vertically upward on the moon how many times higher will it go than it would on Earth if they both have the same initial vel.

Acceleration on moon is 1/6 of what it is on earth

I need some help on solving this. Thank You
 
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Pick an initial velocity, let's say 9.8 m/s to keep it simple. On Earth do you know how high it would go?
 
how do you calculate to get the height?
 
Do you have kinematics formulas? Is this a high school class?
 
yes but i don't have the formulas or the textbook with me but only the questions because this is homework over the summer
 
Without doing any math, do you have a guess as to the answer?
 
is it 96.04m?
 
no. but I didn't mean the answer to my question in the 2nd post of this thread. I meant can you guess at the answer to your original question?
 
it'll go six times higher?
 
  • #10
That wasn't too hard, was it? :)
 
  • #11
o really? that's the right answer but can u teach me how to do it mathematically? because i have to show my work and steps in how to get the answer
 
Last edited:
  • #12
Without doing your work for you, I can't. But there's a few threads similar to this one posted today on this same forum that will give you all the formulas you need. Get the formula, and determine why distance is linear.
 
  • #13
can someone provide me the formulas i can't seem to find any of them in this forum?
 
  • #14
If the acceleration is -a (negative because it is downward) and there is an initial velocity v0 upward, the velocity at time t is v= v0- at and the height is v0t- (1/2)at2. Can you figure out from that the time until the highest point and that height, both in terms of a and v0?
 

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