Solving this question in a certain way

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SUMMARY

This discussion outlines a systematic approach to solving chemical equilibrium problems using the ICE (Initial, Change, Equilibrium) method. The example provided involves a reaction between hydrogen (H2) and iodine (I2) to form hydrogen iodide (HI), with a given equilibrium constant (K) of 10.7. The calculations demonstrate that at equilibrium, the concentration of HI is 0.12 moles per liter when starting with 0.8 moles of H2 and 1.3 moles of I2. A second example is presented, involving the equilibrium of 2A = B + 3C, where the equilibrium constant (K) needs to be determined after mixing specific moles of reactants.

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nhrock3
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this is the general way i solve every question:
example of a solved question in this way

we put 0.8 mole of H2 1.3 mole of I2 in one litter cantainer

the balance constant is 10.7
calculate how much 2HI will be in the container when the reaction balances

H2 +I2 = 2HI
start 0.8 1.3 0
moves -x -x +2x
end 0.8-x 1.3-x 2x

egob5w.gif

there are two solutions but only one is possiblr
x=0.0604
[HI]=0.12how to solve this question in the same way
we mix 0.5 moles of A
1 mole of B
2 moles of C
in a one litter container

after it balances we find 0.6 moles of A
find K for
=(is a sign where two arrows go in different directions)
2A =B+3c
 
Last edited:
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Very nice! Glad to be of assistance.
 

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