Solving Velocity After Falling 268 Feet

[kevindpalmer2]

Homework Statement

Trying to figure how fast you would be falling after 268 feet? not worrying about resistance and in terms of weight just and average person... this is what I did.. is it correct? or way off


vf^2 = vi^2 + 2*a*d
vf^2 = 0 + 2* 9.81 * 90
vf^2 = 1765.8m^2/s^2
take square root
vf = 42 m/s then convert to mph multiply by 2.24? 93.9mph

Homework Equations

vf^2 = vi^2 + 2*a*d
vf^2 = 0 + 2* 9.81 * 90
vf^2 = 1765.8m^2/s^2
take square root
vf = 42 m/s then convert to mph multiply by 2.24? 93.9mph

The Attempt at a Solution

vf^2 = vi^2 + 2*a*d
vf^2 = 0 + 2* 9.81 * 90
vf^2 = 1765.8m^2/s^2
take square root
vf = 42 m/s then convert to mph multiply by 2.24? 93.9mph

 

[SammyS]

That's the correct method. Some of your conversion factors seem to have small errors

90 m ≈ 295.3 ft and 268 ft ≈ 81.69 ft.

etc.

If you want to do it all in US Customary Units, g = 9.81 m/s² ≈ 32.19 ft/s².
and
60 mph = 88 ft/s