Trying to figure how fast you would be falling after 268 feet?

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SUMMARY

The discussion focuses on calculating the final velocity of an object falling from a height of 268 feet, which is approximately 81.7 meters. The formula used is vf² = vi² + 2*a*d, where 'a' is the acceleration due to gravity (9.81 m/s²) and 'd' is the distance fallen. The initial velocity (vi) is zero, leading to a calculated final velocity (vf) of 42 m/s, which converts to approximately 93.9 mph. However, the correct height to use in the calculation is 81.7 meters, not 90 meters, which affects the final result.

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kevindpalmer2
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Trying to figure how fast you would be falling after 268 feet? not worrying about resistance and in terms of weight just and average person... this is what I did.. is it correct? or way off


vf^2 = vi^2 + 2*a*d
vf^2 = 0 + 2* 9.81 * 90
vf^2 = 1765.8m^2/s^2
take square root
vf = 42 m/s then convert to mph multiply by 2.24? 93.9mph
 
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kevindpalmer2 said:
Trying to figure how fast you would be falling after 268 feet? not worrying about resistance and in terms of weight just and average person... this is what I did.. is it correct? or way off


vf^2 = vi^2 + 2*a*d
vf^2 = 0 + 2* 9.81 * 90
vf^2 = 1765.8m^2/s^2
take square root
vf = 42 m/s then convert to mph multiply by 2.24? 93.9mph

This is OK, except that 268 feet is 81.7 meters and not 90
 

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