A jar containing water is kept on the pan of a compression type balance which reads 500 gf. A piece of stone is suspended from the balance and reads 400 gf. The stone when lowered in water weighs 300 gf. What will be the weight of the jar and stone (weighed together) when the stone is immersed in water?
Weight= Weight of jar+Vdg, ie.e. the upthrust because of Newton's third law of motion of equal reaction (opposite.)
The Attempt at a Solution
So the weight=500+(400-300)=600 gf. This answer matches with the answer given at the back of the book. But please can you explain the reason why the apparent weight of the stone is not added to the reading?
I mean to say that it should be equal to 500+100+300. Do you agree??