Force required to immerse a wooden cube

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SUMMARY

The force required to completely immerse a wooden cube with a side length of 4 cm and a relative density (RD) of 0.5 in water is definitively calculated to be 32 x 10-3 kgwt. The calculations involve determining the density of the cube as 0.5 g/cm3 and its volume as 64 cm3. The weight of the cube is calculated using the formula 64 x 10-6 x 500 x 9.8 N, while the upthrust is calculated as 64 x 10-6 x 1000 x 9.8 N. The final force required is derived from the difference between upthrust and weight, confirming option 2) as the correct answer.

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Homework Statement



The force required to immerse a wooden
cube of side 4 cm and relative density RD 0.5 completely in water is
1) 16x10-3 kgwt
2) 32x10-3 kgwt
3) 64x10-3 kgwt
4) 128x10-3 kgwt

Homework Equations

The Attempt at a Solution



Density of the cube = 0.5 gcm-3
Volume of cube = 64 cm3
Weight of the cube = 64 x10-6 x 500 x 9.8 N (1)

Upthrust = 64 x10-6 x 1000 x 9.8 N (2)

Force required = Upthrust - Weight

Subtracting (1) from (2)

Force required = 64 x10-6 x 500 x 9.8 N

1kgwt = 9.8 N

Force required = 32 x10-3 kgwt

Is option 2) the correct answer ?
 
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it looks good to me.
 
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