Solving y"+9y=H(t-1) with Laplace Transform

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SUMMARY

The discussion focuses on solving the differential equation y'' + 9y = H(t-1) using the Laplace Transform method. The participant's proposed solution is y = cos(3t) - (2/3)sin(3t) + (H(t-1)/9)(H(t-1) + cos(3t - 3)). However, this solution is inconsistent with the initial conditions y(0) = 0 and y'(0) = -2, indicating a need for reevaluation. The Heaviside function H(t-1) plays a crucial role in the solution's formulation.

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Fibonacci
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Hi, just like to check my answer with someone for the this question

calculate y"+9y=H(t-1) y(0)=0 y'(0)=-2 using laplace method
H is heaviside fuction

my solution:

y=cos(3t)-2sin(3t)/3 + H(t-1)/9(H(t-1) + cos (3t-3) )

thanks
 
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y(0)=1 for your solution. Not consistent with the given initial value.
 

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