Solving y=e^nx: What's the Result of d^ny/dx^n?

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The discussion revolves around the differentiation of the function y=e^nx and the confusion regarding the result of d^ny/dx^n. The initial assumption was that the result would be n^2e^nx, which is incorrect as it reflects the second derivative rather than the nth derivative. The correct approach requires differentiating n times, not just twice. Participants emphasize the importance of not making assumptions about differentiation orders. Clarifying this misunderstanding is key to solving the problem accurately.
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The problem says that if y=e^nx, then d^ny/dx^n=?

I got that the result is n^2e^nx, but it is not among the offered choices. Can someone tell what did I mess up? Thanks.
 
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You're not differentiating twice, like you did (n^{2}e^{nx}), but "n" number of times.
 
Poop-Loops said:
You're not differentiating twice, like you did (n^{2}e^{nx}), but "n" number of times.


Oh I see. I guess I shouldn't have assumed that it is a second derivative. Thanks for the help.:smile:
 
ludi_srbin said:
Oh I see. I guess I shouldn't have assumed that it is a second derivative. Thanks for the help.:smile:

Yes, in general it is a mistake to assume something when you are told differently!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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