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I need help with solving equation y'=(x^2-y^2)/xy as bernoulli differential equation.
I also tried to do it differently by plugging in y=xv, so I got f(v)=1/v-v.
Finally I got answer y=(+/-) [(x^4+c)^(1/2)]/[(x*2^(1/2)] but I still have no idea how to do it as bernoulli equation
I also tried to do it differently by plugging in y=xv, so I got f(v)=1/v-v.
Finally I got answer y=(+/-) [(x^4+c)^(1/2)]/[(x*2^(1/2)] but I still have no idea how to do it as bernoulli equation