(adsbygoogle = window.adsbygoogle || []).push({}); A charge of 3.19 µC is held fixed at the origin. A second charge of 3.19 µC is released from rest at the position (1.15 m, 0.530 m) .

(a) If the mass of the second charge is 3.10 g, what is its speed when it moves infinitely far from the origin?

ok so i've broken it up into x and y components and used pythagorean theorem to find the line that represents the force that the second charge exerts on the fixed charged [tex]\sqrt{1.15^2 + .530^2}[/tex] and my answer was 1.266 m. Then i used tan[tex]^-1[/tex] (.530/1.15) to find theta which came out to be 11.98[tex]^0[/tex]. Then i calculated 1.266 (cos 11.98) for the positive x-direction and 1.266(sin 11.98) for the positive y-direction and i got 1.2384 m for the x and .26278 m for the y. Then i plugged those values back into pythagorean theorem again to find the net force [tex]\sqrt{.26278^2 + 1.2384^2}[/tex] and got 1.2666N. Then i used the Force per unit charge to find the net electric field and got (1.2666/3.19E-6) = 3.97E5 and multiplied by 2 since there are 2 charges and got 7.94E5 as my net electric field. And then i plugged that value into [tex]\sqrt{2q\Delta V/m}[/tex] to find velocity. Obviously i'm doing something wrong somewhere because i'm not getting the right answer... any help would be greatly appreciated.

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# Homework Help: Some Electric Potential energy questions

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